Home
Class 12
CHEMISTRY
The wavelength correspoding to electroni...

The wavelength correspoding to electronic transition between to orbit of hydrogen atom is 912 Å. The wavelength (in Å) for the same electronic transition in `Li^(2+)` is

A

101.3

B

202.6

C

303.9

D

50.65

Text Solution

Verified by Experts

The correct Answer is:
A
`(a) :. E= (hc)/(lambda), i.e.Ealpha (1)/(lambda) and E alpha (z^(2))/(n^(2)`
for same valueof `(n) E alpha z^(2)`
Thus ,E `alpha z^(2) alpha (1)/(lambda)`
where E = energy ,`lambda` = wavelength
z = atomic number
There for `Z _((H))`
`Z_((Li)) = 3 " "implies " " lambda _((H)) = 921`Å
`alpha _((Li)) = ` To find
` (Z_((H))^(2))/(Z_((Li))^(2)) = (lambda_((Li)))/(lambda _((H))) or lambda _((Li)) = (1 xx912)/(9)`
`lambda _((Li))101.3`Å
Promotional Banner

Similar Questions

Explore conceptually related problems

The potential energy of an electron in the fifth orbit of hydrogen atom is

The wavelength of the electron in the first orbit of the Hydrogen atom is x. The wave length of the electron in the third orbit and the circumference of the third orbit of the Hydrogen atom are respectively

The wavelength of spectral line for electron transition is inversely related to

The fourth line of the Balmer series corresponds to the electronic transition between two orbits the H atom, Identify the orbits.

The fourth line of the Balmer series corres ponds to the electronic transition between two orbits of the H atom, Identify the orbits.

in the Bohr hydrogen atom, the electronic transition emmiting light of longest wavelength is

In an electron transition of hydrogen atom orbital momentum may change by :

The circumference of first orbit of hydrogen atom is .S.. Then the Broglie wavelength of electron in that orbit is