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To 50ml of 0.1 N Na -(2) CO(3) solution ...

To 50ml of 0.1 N `Na -(2) CO_(3)` solution 150ml of water is added . What is the molarity of result solution ?

A

`(M)/(40)`

B

`(M)/(20)`

C

`(M)/(80)`

D

`(M)/(30)`

Text Solution

Verified by Experts

The correct Answer is:
C
`:.` Init ial volume` (V_(1))= 50mL`
Initial normality ` (N_(1))= 0.1N`
final volume `(V_(2) ) = 50+150 = 200mL`
final normality `(N_(2)) =`To find and ` N_(1) xx V _(1) = N_(2) xx V_(2) 01xx50 = (=N) xx 200`
`:." " N_(2) = ((0.1xx50)N)/ (200)=(N)/(40)`
Also Z for `Na_(2) CO_(3) =2`
(where ,Z = total positive charge in `Na _(2) CO_(3) `) and N (normality ) `= M xx Z ` (where M is molarity ).
`:.` Molarity of resultant solution `=(N) / (40) XX (1)/(2)=(M)/(80)`
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