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Using the standard electrode potentials...

Using the standard electrode potentials given below identify the correct statement from the following .
`Fe ^(2)+2e^(-)rarrFe,E^(@)=-0.44V`
`Cu ^(2+)+2e^(-)rarr Cu,E^(@)=-0.34V`
`Ag ^(+)e^(-)rarr Ag,E^(@)=-0.80V`
(i) Copper can displace iron from `FeSO_(4)` solution .
(ii) Iron c an displace copper from `CuSO_(4)` solution .
(iv) Iron can displace silver from `AgNO_(3)` solution.

A

(i),(ii),

B

(ii),(iii)

C

(ii),(iv)

D

(i),(iv)

Text Solution

Verified by Experts

The correct Answer is:
C
`Fe^(2+) + 2e^(-) rarr Fe, E^(@) = - 0.44`
`Cu^(2) + 2e^(-) rarr Cu, E ^(@) = + 0.34`
`Ag + le^(-) rarr Ag E^(@) = + 0.84`
If a metal have negative electrode potential than metal easily displace , other metal , I,e, Fe can displace Cu and Ag.
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