Aqueous sulphite reacts with dilute sulphuric acid to form X (g ). The liberated X ( g) is passed into acidifield `KMnO_(4)` solution . What is the oxidation state of Mn in the product formed ?

Options

A. `+6`
B. `+4`
C. `+2`
D. `+3`

Answer

C

Explanation

Aqueous sulphite when reacts with sulphuric acid it gives `SO_(2)` (g) which when react (passed) with acidifield `KMnO_(4)` gives `Mn^(2+)` ions as follows :
`(i) SO_(3)^(2+) + H_(2) SO_(4) to SO_(4)^(2-) + SO_(2) + H_(2)O`
`(ii) 5SO_(2) + 2KMnO_(4) + 2H_(2)O to K_(2) SO_(4)`
`:.` Oxidation state of Mn in `MnSO_(4) ` is + 2
Hence option ( c) is the correct answer