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An ideal solution of hexane and heptane ...

An ideal solution of hexane and heptane at `30^(@)C` has a vapour pressure of 95 bar with hexane mole fraction 0.305. in vapour phase hexane mole fraction is 0.555. The vapour pressure of pure hexane and heptane at `30^(@)C` respectively in bar are

A

172.9, 60.9

B

60.8, 172.9

C

30.4, 86.5

D

86.5, 30.4

Text Solution

Verified by Experts

The correct Answer is:
A

Given, a vapour pressure of ideal solution of hexane `(p_(T))=95` bar
Mole fraction of hexane `(S_(A))=0.305`
So, `" "(X_(B))=1-0.305=0.695`
Mole fraction of vapour phase hexane `(Y_(A))=0.555`
and heptane `(Y_(B))=1-0.555=0.445`
From Raoult.s law,
Vapour pressure of hexane `=p_(A)^(@)`
Vapoure pressure of heptane `=p_(B)^(@)`
`p_(T)(Y_(A))=p_(A)^(@)(X_(A)), p_(T)(Y_(B))=p_(B)^(@)(X_(B))`
`95(0.555)=p_(A)^(@)(0.305), 95(0.445)=p_(B)^(@)(0.695)`
`p_(A)^(@)=172.9 " bar, "p_(B)^(@)=60.9` bar
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