For the gaseous reactions (I) and (II) the equilibrium constants are X and Y respectively.
I. `(1)/(2)N_(2)(g) + O_(2) (g) hArr NO_(2)(g)`
(II) `2NO_(2)(g) hArr N_(2)O_(4) (g)` Using the above reactions the equilibrium constant Z for the reaction (III) given below is
III. `N_(2)O_(4)(g) hArr N_(2)(g) + 2O_(2) (g)`

Options

A. Z= XY
B. `Z = (Y^(2))/(X)`
C. `Z = (1)/(XY^(2))`
D. `Z = (1)/(X^(2)Y)`

Answer

D