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If the ratio of energies of electron in ...

If the ratio of energies of electron in the excited states of H and `Li^(2+)` is 1 : 9, the radius ratio of electron in the same excited states of H and `Li^(2+)` is

A

`9:1`

B

`3:1`

C

`1:9`

D

`1:3`

Text Solution

Verified by Experts

The correct Answer is:
B
`because` For same excited state
`rprop1/ZandEpropZ^(2)`
Where, r = redius of element
Z = atomic number of element
.Z. for (H) and `(Li^(2+))` are 1 and 3 respectively thus,
`(r_(H))/(r_((Li^(2+))))=(Z_((Li^(2+))))/(Z(H))`
`r_((H))/r_((Li^(2+)))=3/1=3:1`
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