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If the ionization constant of hypochloro...

If the ionization constant of hypochlorous acid (HOCl) is `2.5xx10^(-5)`, the pH of 1.0 M of its solution is `(log5=0.7)`

A

3.3

B

2.3

C

4.3

D

`3.0`

Text Solution

Verified by Experts

The correct Answer is:
B
Given, ionisation constant `(K_(a))=2.5xx10^(-5)`
and molarity ( c) = 1.0 M
`becauseK_(a)=Calpha^(2)" "(becausealphaltlt1)`
`therefore" "alpha=sqrt(K_(a)/C)=sqrt((2.5xx10^(-5))/1)`
= `0.5xx10^(-3)`
or `alpha=5xx10^(-3)`
Also, for dissociation of HOCl, the required relation is as follows

`therefore[H^(+)]=alpha=5xx10^(-4)`
and `pH=-log[H^(+)]`
= `-log[5xx10^(-3)]`
= `-log5+3log10`
= - 0.7 + 3
pH = 2.3
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