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Propyne reacts with HBr to form Z. The c...

Propyne reacts with HBr to form Z. The compound Z is

A

`CH_(2)(Br)CH_(2)CH_(2)Br`

B

`CH_(3)CH_(2)CHBr_(2)`

C

`CH_(3)CH(Br)CH_(2)Br`

D

`CH_(3)CBr_(2)CH_(3)`

Text Solution

Verified by Experts

The correct Answer is:
D
`underset("Propyne")(CH_(3)-CH-=C-H_(2))overset(H-Br)tounderset((Z))underset("2,2 dibromo propane")(CH_(3)-underset(Br)underset(|)overset(Br)overset(|)(C)-CH_(3))`
This is the electrophilic addition so the product will be 2, 2 - dibromo propane.
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