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Calcium phosphide reacts with water to f...

Calcium phosphide reacts with water to form `Ca(OH)_(2)` and X. When X is placed into `CuSO_(4)` solution. Y and `H_(2)SO_(4)` are formed. What is Y?

A

`[Cu(PH_(3))_(4)]^(2+)`

B

`[Cu(PH_(3))_(6)]^(2+)`

C

`Cu_(3)P_(2)`

D

`CuHPO_(4)`

Text Solution

Verified by Experts

The correct Answer is:
C
Calcium phosphide reacts with water to form calcium hydroxide and phosphine.
`underset("Phosphide")underset("Calcium")(Ca_(3)P_(2))+underset("Water")(6H_(2)O)tounderset("Calcium hydroxide")(3Ca(OH)_(2)aq)+underset((Y))underset("Phosphine")(2PH_(3)(g))`
Phosphine when passed into `CuSO_(4)` solution, it reacts to produce black precipitate of cupric phosphide and `H_(2)SO_(4)`.
`underset("Phosphine")(3PH_(3))+underset("Copper sulphate")(3CuSO_(4))tounderset("Cupric phosphide")(Cu_(3)P_(2))+underset("Sulphuric acid")(3H_(2)SO_(4))`
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