If the electronic congiguration of `M^(3+)` is `[Xe]4 d^(3)`, then `M^(3+)` is

Options

A. `Nd^(3+)`
B. `Pr^(3+)`
C. `Sm^(3+)`
D. `Dy^(3+)`

Answer

A

Explanation

Given, the electronic configuration of `M^(3+)` is `[Xe] 4 f^(3)`.
The electronic configuration of metals given in options in `M^(3+)` are as follows :
(a) `Nd^(3+) = [Xe] 4f^(3)`
(b) `Pr^(3+) = [Xe] 4 f^(2)`
(c ) `Sm^(3+) = [Xe] 4 f^(2)`
(d) `D y^(3+) = [Xe] 4 f^(9)`
Thus, `M^(3+)` among the given options will be `Nd^(3+)`.