The opposite faces of a glass slab of thickness 15 cm are parallel. If a ray of light is incident on the glass slab at an angle `60^(@)`, calculate the lateral displacement of the ray when it emerges from the slab. `[mu " "" of glass" = 1.5]`

Explanation

Lateral displacement of a ray of light incident at an angle I on a parallel glass slab having thickness t
`= tsini [1 - (cosi)/(mu^(2) - sin^(2)i)][mu = 1.5]`
`= 15 sin 60^(@) [1 - (cos60^(@))/(sqrt(((3)/(2))^(2) -sin^(2)60^(@))]]`
`= 15 xx (sqrt3)/(2) [1 - (1/2)/(sqrt((9)/(4) - (3)/(4)))] = 7.69 cm`