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There is a mark at the bottom of a beake...

There is a mark at the bottom of a beaker. A liquid of refractive index 1.4 is poured into it. If the depth of the liquid is 3.5 cm then determine how much will the mark appear to rise when it is viewed from above?

Text Solution

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If the object is in denser medium and the observer is in rarer medium, refractive index of the denser medium relative to the rarer medium
`= ("real depth of the objet")/("apparent depth of the object")`
`or, " " 1.4 = (3.5)/("apparent depth of the object")`
`or, "apparent depth of the object" = (3.5)/(1.4) = 2.5 cm`
`therefore " "` apparent upward displacement of the mark
`= 3.5 - 2.5 = 1cm`
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