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A 20 mm thick layer of water (mu=(4)/(3)...

A 20 mm thick layer of water `(mu=(4)/(3))` floats on a 35 mm thick layer of another liquid `(mu=(7)/(5))` in a tank. A small coin lies at the bottom of the tank. Determine the apparent depth of the coin when viewed normally from above the water.

Text Solution

Verified by Experts

Real depth of the coin = `d_(1) + d_(2) = 20 + 35 = 55mm`
`therefore` Apparent depth of the coin
`= (d_1)/(d_(2)) + (d_(2))/(mu_(2))l = (20)/(4) + (35)/(7) = 15 + 25mm`
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