Home
Class 12
PHYSICS
The refractive index of the material of ...

The refractive index of the material of a prism is `sqrt((3)/(2)` and the refractive angle is `90^(@)` . What are the values of the angle of minimum deviation of the prism and the angle of the incidence at the minimum deviation position?

Text Solution

Verified by Experts

`"Here" " " A = 90^(@), mu = sqrt((3)/(2)). "Let the angle of the minimum deviation be" delta_(m)`.
e`"We know", mu = (sin""(A + delta_(m))/(sin""(A)/(2))) = (sini_(1))/(sinr_(1))`
`therefore" " sqrt((3)/(2)) = sin""(90^(@) + delta_(m))/(sin""(90^(@))/(2))= sin""(90^(@) + delta_(m))/(sin 45^(@))`
`or, " " sin""(90^(@) + delta_(m))/(2) = sqrt((3)/(2) ) xx sin 45^(@) = sqrt(3)/sqrt(2) xx (1)/(sqrt(2)) = (sqrt(3))/(2)`
`therefore " " i_(1) = (90^(@) + delta_m)/(2) = 60^(@) or, 90^(@) + delta_(m) = 120^(@)`
`or, " " delta_(m) = 30^(@) therefore r_(1) = (A)/(2) = (90^(@))/(2) = 45^(@)`
Promotional Banner

Topper's Solved these Questions

  • REFRACTION OF LIGHT

    CHHAYA PUBLICATION|Exercise HIGHER ORDER THINKING SKILL (HOTS QUESTION)|25 Videos

  • REFRACTION OF LIGHT

    CHHAYA PUBLICATION|Exercise SECTION RELATED QUESTION|18 Videos

  • REFLECTION OF LIGHT

    CHHAYA PUBLICATION|Exercise INTEGER ANSWER TYPE|3 Videos

  • SEMICONDUCTORS AND ELECTRONICS

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|31 Videos

Similar Questions

Explore conceptually related problems

The refractive index of the material of a prism is sqrt((3)/(2)) and the refracting angle is 90^(@) The angle of minimum deviation of the refracted ray by the prism is

The refractive index of the material of a prism is sqrt((3)/(2) and the refractive angle is 90^(@) . Calculate the angle of minimum deviation and the corresponding angle of incidence. Show that the limiting angle of incident for getting emergent ray is 45^(@) .

Refractive index of the material of an equilateral prism is sqrt(2) .

The refractive index of the material of a prism is sqrt(2) and the angle of minimum deviation is 30^(@) . Calculate the value of the refracting angle of the prism.

The refractive index of a prism is sqrt(2) and its refractive angle is 60^(@) . If a ray emerge with the minimum angle of deviation then the angle of incidence will be

In case of refraction, angle of deviation becomes minimum when the angle of incidence becomes

Write down the condition for minimum deviation in prism.

The angle of prism is A and refractive index is cot A/2 . The minimum deviation of the prism—

For green light the refractive index of prism, of refractive angle 5^(@) , is 1.5. What will be the value of the minimum angle of deviation of a green light?