A light ray is incident on one refraction face of a prism, of refractive angle A, at an angle of incidence, I and emerges from the opposite face, normally. If refractive index of the material of the prism be `mu` what will be the value of the angle of incidence?

A very thin prism deviates a ray of light through 5^(@) . If the refractive index of the material of the prism is 1.5 , what is the value of the angle of prism?

At what angle should a ray of light be incident on the face of a prism of refractive angle 60^(@) so that it just suffers total internal reflection at the other face? The refractive index of the material of the prism is 1.524 .

The refracting angle of a prism is A, and refractive index of the material of the prism is cot (A // 2) . The angle of minimum deviation is

The refractive angle of prism is A. A ray is incident normally on one of the refracting faces of a prism and emerges out. If D be the deviation of the ray then refractive index of the material of the prism is—

A ray of light is incident on a prism of refractive index mu and angle A at the angle of incidence i_(1) and emerges at the angle i_(2) . If the ray is incident on the prism at the angle i_(2) , calculate the deviation of the ray.

A ray of monochromatic light enters a prism of angle 'A’ at grazing incidence and emerges at an angle theta to the normal on the opposite face. Show that refractive index mu of the material of the prism is given by mu = [ 1+ ((sin theta + cos A)/ (sin A))^2]^(1/2) .

Find the value of the limiting angle of incidence if the refractive index of the material of prism is 1.333 and angle of prism is 60^(@) .