Calculate the speed of light in a medium whose critical angle is `45^(@)`.

Answer

If `theta_(c)` is the critical angle of any medium with respect to vacuum or air and `mu` is the refractive index of the medium, `sintheta_(c) = (1)/(mu)`
According to the question,
`mu = (1)/(sintheta_(c)) = (1)/(sin45^(@)) = (1)/((1)/(sqrt(2))) = sqrt(2)`
Velocity of light in air or vacuum,
`c = 3 xx 10^(8)m//s`
`therefore " " "Velocity of light in the medium"`
`v = (c)/(mu) = (3 xx 10^(8))/(sqrt(2)) = 2.12 xx 10^(8) m//s`
2nd part : N/A