s-t graph for a partical, moving with a constant acceleration, subtends `45^(@)`angIe with the time axis at time t. That angle becomes `60^(@)` 1s Iater. Find the acceleration of the partical.

Explanation

Let the velocity of the particle at `P_(1)` and `P_(2)` be u and v respectively .
u = tan `theta_(1)` and v = `tan theta_(2)`
Acceleration of the particle
a `= (v-u)/(t_(2) -t_(1))`
`= (tan theta_(2) -tantheta_(1))/(t_(2)-t_(1))`
`= (tan 60^(@) - tan 45^(@))/(1)`
`= sqrt(3-1)` = 0.732 unit . `s^(-2)`.