A stone is dropped from a height of 19.6m. What is the time taken by the stone to travel the last metre of the path?

Explanation

In this case u = 0
`:. " " h = (1)/(2) "gt"^(2) " ""or", t = sqrt((2h)/(g))`
Let `t_(1)` and `t_(2)` be the time taken by the stone to travel (19.6 -1) = 18.6m and 19.6 m. respectively.
`:." " t_(1) = sqrt((2xx18.6)/(9.8)) " ""and"" "t_(2) = sqrt((2xx19.6)/(9.8))`
or, `" " t_(1) = 1.948 s " ""and" " "t_(2) = 2s `
Hence the time taken to travel the last metre ,
`t_(2)-t_(1) = 2-1.948 = 0.052` s.