Home
Class 11
PHYSICS
Distance covered by a particle moving in...

Distance covered by a particle moving in a straight line from origin in time t is given by x = t-`6t^(2)+t^(3)` . For what value of t, will the particle's acceleration be zero?

Text Solution

Verified by Experts

The correct Answer is:
t = 2 s
Promotional Banner

Topper's Solved these Questions

  • ONE - DIMENSIONAL MOTION

    CHHAYA PUBLICATION|Exercise Problem Set - I (Based on Rectilinear Motion )|13 Videos

  • ONE - DIMENSIONAL MOTION

    CHHAYA PUBLICATION|Exercise Problem Set - I (Based on Vertical Motion )|11 Videos

  • ONE - DIMENSIONAL MOTION

    CHHAYA PUBLICATION|Exercise Short Answer Type Questions -II|8 Videos

  • NEWTONIAN GRAVITATION AND PLANETARY MOTION

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|19 Videos

  • QUESTION PAPERS OF NEET -2017

    CHHAYA PUBLICATION|Exercise QUESTION|32 Videos

Similar Questions

Explore conceptually related problems

If the distance from the initial point at a time t is given by x = t - 6t^2 + t^3 : then at what time the acceleration will be zero?

The distance S metres moved by a particle traveling in a straight line in t second is given by S = 45t +11t^2-t^3 . Find the time when the particle comes to rest.

A particle is moving in a straight line. At time, the distance between the particle from its starting point is given by x=t-6t^(2)+t^(3) . lts acceleration will be zero at

The space s described in time t by a paricle moving in a strainght line is given by , s=t^(5)-40t^(3)+30t^(2)+80t-250 . Find the minimum value of its acceleration.

The distance travelled by an object along a straight line in time 't' is given by S = 3 - 4t + 5t^(2) , the initial velocity of the object is

For a particle travelling along a straight line the equation of motion is s = 16 t+5 t^(2) . Show that it will always travel with uniform acceleration.

A particle moves along X-axis and its displacement at any time is given by x(t) = 2t^(3) -3t^(2) + 4t in SI units. The velocity of the particle when its acceleration is zero, is

A particle moves in a straight line and its velocity v (in cm/s ) at time t (in second ) is 6t^(2) - 2t^(3) , find its acceleration at the end of 4 seconds.

The displacement of a particle starting from rest (at t = 0) is given by s = 6t^(2)-t^(3) . The time in second at which the particle obtain zero velocity again is