Home
Class 11
PHYSICS
The coordinates of a body at time t are ...

The coordinates of a body at time t are x = 7t+`4t^(2)` and y = 5t, where x and y are in metres and t in seconds . What its acceleration at t = 5s?

Text Solution

Verified by Experts

The correct Answer is:
8 m.`s^(-2)`
Promotional Banner

Topper's Solved these Questions

  • ONE - DIMENSIONAL MOTION

    CHHAYA PUBLICATION|Exercise Problem Set - I (Based on Rectilinear Motion )|13 Videos

  • ONE - DIMENSIONAL MOTION

    CHHAYA PUBLICATION|Exercise Problem Set - I (Based on Vertical Motion )|11 Videos

  • ONE - DIMENSIONAL MOTION

    CHHAYA PUBLICATION|Exercise Short Answer Type Questions -II|8 Videos

  • NEWTONIAN GRAVITATION AND PLANETARY MOTION

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|19 Videos

  • QUESTION PAPERS OF NEET -2017

    CHHAYA PUBLICATION|Exercise QUESTION|32 Videos

Similar Questions

Explore conceptually related problems

The x and y coordiates of a particle at any time t are given by x = 7t + 14 t^(2) and y = 5t, where x and y are in metre and t is in second. The acceleration of the particle at t = 5 s is

The position coordinate of a moving particle is given by x = 6+18t +9 t^(2) (where x is in metre, t in seconds. What is its velocity and acceleration at t = 2 s.

Equations of trajectory of a projectile are x=4 t, y= 3t - 5 t ^(2) , where x and y are in metre and t is in second . Find (i) maximum height attained by the projectille , (ii) horizontal range of the projectile .

The velocity of a moving particle is given by v = 6 +18t + 9t^(2) (x in metre t in second ) what is its acceleration at t = 2 s?

Equation of a wave is given by y = 10^(4) sin(60t + 2x) , x & y in metre and t is in second. Then

Displacement x and time t, in a rectiIinear motion of a partical are reIated as t = sqrt(x)+3 . Here x is measured in metre and t in second. Find the displacement of the partical when its velocity is zero.

The relation between the time taken and the displacement of a moving body is s = 2t - 3t^(2) + 4t^(3) , where the unit of s is in metre and that of t is in second. Find out the displacement, velocity and acceleration of the body 2s after initiation of the journey.

The motion of a body is defined by (dv(t))/(dt) = 6-3 v(t) where v (t) is the velocity (in m/s ) of the body at time t (in seconds ). If the body was at rest at t= 0 , find its velocity (in m/s ) when the acceleration is half the initial value.

The relation between the displaement x and the time t for a body of mass 2 kg moving under the action of a force is given by x=t^3//3 , where x is in metre and t in second . Calculate the work done by the body in the first 2 seconds .