Home
Class 11
PHYSICS
A particle covers 25 cm and 33 cm in the...

A particle covers 25 cm and 33 cm in the 5 th and 7 th seconds respectively. What is the velocity of the particle 9 seconds after the initiation of the journey?

Text Solution

Verified by Experts

The correct Answer is:
43 cm.`s^(-1)`
Promotional Banner

Topper's Solved these Questions

  • ONE - DIMENSIONAL MOTION

    CHHAYA PUBLICATION|Exercise Problem Set - I (Based on Vertical Motion )|11 Videos
  • ONE - DIMENSIONAL MOTION

    CHHAYA PUBLICATION|Exercise Problem Set - II (Based on Speed, Velocity and Acceleration )|4 Videos
  • ONE - DIMENSIONAL MOTION

    CHHAYA PUBLICATION|Exercise Problem Set - I (Based on Speed, Velocity and Acceleration )|10 Videos
  • NEWTONIAN GRAVITATION AND PLANETARY MOTION

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|19 Videos
  • QUESTION PAPERS OF NEET -2017

    CHHAYA PUBLICATION|Exercise QUESTION|32 Videos

Similar Questions

Explore conceptually related problems

A particle moves with a uniform acceleration along a straight line. It covers 41 cm and 49 cm in the 6th and the 10th seconds respectively. What will be the distance covered by the particle in 15 s?

An object moving with a constant acceleration covers 145 cm and 185cm, during its 6th and 10th second of motion respectively. What distance would it cover in the 16th second?

The initial velocity of a particle- is u and acceleration (f) is uniform. Final velocity and distance covered in the interval t are v and s respectively. Show that the velocity of the particle at half - distance is more than the velocity for half-time.

The initial velocity is u and acceleration (f) is uniform. Final velocity and distance covered in the interval t are v and s respectively. Show that the velocity of the particle at half-distance is more than the velocity for half -time.

A partical covers 35 cm, 50 cm, 89 cm distances during the third, seventh and tweIfth seconds respectiveIy of ite motion. Show that the partical is moving with a constant acceleration. Find (i) initial velocity and (ii) distance covered in 8 s by the partical.

The motion of a particle, along x-axis, follows the relation x = 8t- 3t^(2) . Here x and t are expressed in metre and second respectively . Find (i) the average velocity of the particle in time interval 0 to 1 s and (ii) its instantaneous velocity at t = 1 s.

A particle starts from the origin and moves along a straight line. If the velocity of the particle at time t seconds be 10t cm/s, find the distance traversed during first 4 seconds after the start.

The acceleration of a particle moving along a straight line is (6t^(2)-3t)cm//s^(2) , at time t seconds. If the velocity of the particel at time 2 seconds be 10cm/s, find its velocity at time t seconds.

Define centre of mass..Write down its mathematical form. Two particles of masses 2g and 3g are situated at.the positions (2cm.3cm) and (4cm, 5 cm) respectively. Find the position vector o'f the centre of mass of the two particles.

A particle moves with uniform acceleration and the distance travelled in t - th second is s_(t) = 3 + 2t . Find the initial velocity of the particle .