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An object moving with a speed of 6.25 "m...

An object moving with a speed of 6.25 `"m.s"^(-1)` is decelerated at a rate given by:
`(dv)/(dt) = -2.5 sqrt(v)`
where v is the instantaneous speed. What would be the time taken by the object to come to rest?

Text Solution

Verified by Experts

The correct Answer is:
2 s
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