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A particle was at x =0 at t = 0 . It mov...

A particle was at x =0 at t = 0 . It moves with velocity v along the positive x -axis . If v changes with respect to x following the rule v = k `sqrt(x)` , how do its velocity and acceleration change with time?

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The correct Answer is:
`v = (1)/(2) K^(2)t, a = (1)/(2) k^(2)`
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