Home
Class 11
PHYSICS
A object falls from rest through a resis...

A object falls from rest through a resistive medium. The equation of its motion is `(dv)/(dt) = alpha -beta`v. Then

A

the initial acceleration = `alpha`

B

at time t , the velocity = `(alpha)/(beta) (1 - e^(-betat))`

C

when the acceleration is zero the velocity `= (alpha)/(beta)`

D

the constant `beta` has the dimension of time

Text Solution

Verified by Experts

The correct Answer is:
A, B, C
Promotional Banner

Topper's Solved these Questions

  • ONE - DIMENSIONAL MOTION

    CHHAYA PUBLICATION|Exercise ENTRANCE CORNER ( Comprehension type )|3 Videos
  • ONE - DIMENSIONAL MOTION

    CHHAYA PUBLICATION|Exercise ENTRANCE CORNER ( Integer answer type )|5 Videos
  • ONE - DIMENSIONAL MOTION

    CHHAYA PUBLICATION|Exercise ENTRANCE CORNER (Assertion-reason type )|12 Videos
  • NEWTONIAN GRAVITATION AND PLANETARY MOTION

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|19 Videos
  • QUESTION PAPERS OF NEET -2017

    CHHAYA PUBLICATION|Exercise QUESTION|32 Videos

Similar Questions

Explore conceptually related problems

An electron falls from rest through a vertical distance h in a uniform and vertically upward directed electric field E. The direction of electric field is now reversed, keeping its magnitude the same. A proton is allowed to fall from rest in it through the same vertical distance h. The time of fall of the electron, in comparison to the time of fall of the proton is

A body falling freely from a certain height travels half of that height in the last second of its motion. Find the height from which it stated to fall.

An object falling from rest in air is subject not only to the gravitational force but also to air resistance. Assume that the air resistance is proportional to the velocity with constant of proportionality as k >0 , and acts in a direction opposite to motion (g=9. 8 m/(s^2))dot Then velocity cannot exceed. ( a ) 9.8/k" "m//s (b) 98/k" "m//s (c) k/9.8 m/s (d) None of these

If the axes are transferred to parallel axes through the point (alpha ,- beta), then the equation of the circle (x- alpha)^(2) +(y - beta )^(2) =a^(2) reduces to the form-

Starting from rest, a train traveIs a certain distance with a uniform acceleration alpha . Then it traveIs with a uniform retardation beta and finally comes to rest again. If the totaI time of motion is t,find (i) the maximum velocity attained and (ii) the totaI distance travelled by the train.

A bar magnet falls from height 'h' through a metal ring as shown in the figure. Will its acceleration be equal to 'g'? Give reason for your answer.