A car travelling on a straight road moves with a uniform velocity `v_(1)` for some time and with uniform velocity `v_(2)` for the next equal time. The average velocity of the car is

Options

A. `sqrt(v_(1)v_(2))`
B. `(1)/(v_(1))+(1)/(v_(2))`
C. `(1)/(2)((1)/(v_(1))+(1)/(v_(2)))`
D. `((v_(1)+v_(2)))/(2)`

Answer

D

Explanation

If the car travels with velocity `v_(1)` for time t and then with velocity `v_(2)` for time t then the displacement in time 2t= `v_(1)t+v_(2)t=(v_(1)+v_(2))t`
`:.` Average velocity = `((v_(1)+v_(2)))/(2t)=(v_(1)+v_(2))/(2)`