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The velocity of a moving particle is giv...

The velocity of a moving particle is given by v = 6 +18t + `9t^(2)` (x in metre t in second ) what is its acceleration at t = 2 s?

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Given v = 6 +18t+9`t^(2)`
`:.` Acceleration `a =(dv)/(dt) = 18 +18 t`
Hence acceleration at t = 2 s is
` (dv)/(dt)|_(t=2) = 18+18xx2 = 54 m//s^(2)`
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CHHAYA PUBLICATION-ONE - DIMENSIONAL MOTION -CBSE SCANNER
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