A stone is allowed to fall from the top of a tower 100m high and at the same time another stone is projected vertically upwards from the ground with a velocity of 25m/s. Calculate when and where the two stones will meet. `( g=10m/s^(2))`

Explanation

The initial velocity of the first stone is zero and that of the second stone is in the horizontal direction. Hence, the vertical component of the initial velocity of the second stone is also, zero, Consequently the two stones will touch the ground at the same instant, but not at the same point. Due to an initial horizontal velocity, the second stone will have some horizontal displacement.