Home
Class 11
PHYSICS
The maximum height attained and the rang...

The maximum height attained and the range of a projectile are H and R respectively. If projected with an initial velocity of u, show that, `R^2=16H((u^2)/(2g)-H).`

Promotional Banner

Topper's Solved these Questions

  • VECTOR

    CHHAYA PUBLICATION|Exercise PROBLEM SET-II (Hot Numerical Problems)|24 Videos

  • VECTOR

    CHHAYA PUBLICATION|Exercise ENTRANCE CORNER (Assertion -reason type)|12 Videos

  • VECTOR

    CHHAYA PUBLICATION|Exercise PROBLEM SET-I|59 Videos

  • THERMOMETRY

    CHHAYA PUBLICATION|Exercise EXAMINATION ARCHIEVE - WBJEE|1 Videos

  • VISCOSITY AND SURFACE TENSION

    CHHAYA PUBLICATION|Exercise EXERCISE (CBSE SCANNER)|9 Videos

Similar Questions

Explore conceptually related problems

Maximum height of a projectile is H an range of projection is R when the projectile is projected with the velocity u. Show that R^2 = 16H (u^2/(2g)-H) .

If the base radius and height of a right circular cone are 2R and H respectively, then the area of total surface of the cone is

The maximum range of a projectile is 2/sqrt3 times its actual range. What is the angle of projection for the actual range?

Show that the maximum height attained by a projectile is one fourth of its maximum horizontal range.

If the height, slant height and diameter of base of a right ciecular cone are h, l, d respectively then the value of (l^2 - h^2)/(d^2) is

During the n th second of its motion a body covers a distance s_(n) with uniform acceleration a and initial velocity u. Show that a = (2s_(n)-2u)/(2n-1) .

The height and radius of the cone of which the frustum is a part are h_1 and r_1 respectively. If h_2 and r_2 are the heights and radius of the smaller base of the frustum respectively and h_2 : h_1 = 1 :2, then r_1 : r_2 is equal to__

A body is sliding down an inclined plane of inclination theta with a uniform velocity. If the body is projected with a velocity u along the plane upwards, show that it will ascend a distance u^2//4g sin theta along the plane.

A body is projected from the ground with a velocity vec(v)= (3 hat(i) + 10 hat(j)) ms^(-1) . The maximum height attained and the range of the body respectively are (given g= 10 ms^(-2) )

CHHAYA PUBLICATION-VECTOR-PROBLEM SET-II
  1. If |vecAxxvecB|=sqrt(3)vecA*vecB, then show that |vecA+vecB|=sqrt(A^...

    Text Solution

    |

  2. vecA,vecB and vecC are unit vectors, vecA*vecB=vecA*vecC=0 , and the a...

    Text Solution

    |

  3. veca1 and veca2 two non-collinear unit vectors and |veca1+veca2|=sqrt(...

    Text Solution

    |

  4. A body is thrown horizontally with velocity 122 m *s^(-1) from the top...

    Text Solution

    |

  5. The maximum height attained and the range of a projectile are H and R ...

    Text Solution

    |

  6. A fighter plane flying horizontally at an altitude of 1.5 km with spe...

    Text Solution

    |

  7. Find the angle of projection of a projectile for which the horizontal ...

    Text Solution

    |

  8. A particle is projected with a velocity of 20 m/s at an angle of 30^@...

    Text Solution

    |

  9. A stone ,thrown with the same initial speed ,rises 20 m higher when t...

    Text Solution

    |

  10. A bullet is fired with a velocity of 900 km/h in the horizontal direct...

    Text Solution

    |

  11. A bullet is fired with a velocity of 900 km/h in the horizontal direct...

    Text Solution

    |

  12. A bullet is fired with a velocity of 10m/s^(2) at an angle 30^(degree)...

    Text Solution

    |

  13. Two particles are projected simultaneously with the same initial veloc...

    Text Solution

    |

  14. The resultant velocity of a projectile at its highest point is sqrt(6...

    Text Solution

    |

  15. Maximum and minimum values of the resultant of two forces, acting at...

    Text Solution

    |

  16. At 10.a.m.., a ship A is at 40 km to the east of a ship B . Ship A ...

    Text Solution

    |

  17. Two vectors hati+hatj+2hatk and hati+hatj-hatk represent two sides of...

    Text Solution

    |

  18. In a trapezium ABCD vec(AB)=3hati, vec(AD)=hati+2hatj ,vec(DC)=2hati....

    Text Solution

    |

  19. The position vector of a particle is given by vecr=3.0t hati-2.0t^2h...

    Text Solution

    |

  20. The position vector of a particle is given by vecr=3.0t hati-2.0t^2h...

    Text Solution

    |