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Locus of the path of a projectile , in a...

Locus of the path of a projectile , in a vertical plane is given by , =ax-`bx^2`, where a and b are constants and the horizontal and the vertical distances from the point of projection are x and y , respectively. Find the maximum height attained and the the angle of projection with the horizontal.

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The correct Answer is:
`(a^2)/(4b), tan ^(-1)`a
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