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Show that for a projectile the angle bet...

Show that for a projectile the angle between the velocity and the x-axis as a function of time is given by
`theta(t)=tan^(-1)((u_y-"gt")/(u_x))`

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Show that the projection angle theta_0 for a projectile launched from the origin is given by theta_0=tan^(-1)((4H)/R) Where the symbols have their usual meaning.

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Maximum height of a projectile is H an range of projection is R when the projectile is projected with the velocity u. Show that R^2 = 16H (u^2/(2g)-H) .

If 2u = 5x is the relation between the variables x and u and geometric mean of x is 1, find the geometric mean of u.

If theta is the angle between the lines given by the equation 6x^2+5x y-4y^2+7x+13 y-3=0 , then find the equation of the line passing through the point of intersection of these lines and making an angle theta with the positive x-axis.

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