Magnitudes of two forces acting at a point are in the ratio of `2:1` . If the angle between their resultant and the greater force is `theta` , show that, the value of `theta` cannot exceed `(pi)/(6)`.

Maximum and minimum values of the resultant of two forces, acting at a point, are 15 N and 7N respectively. If the value of each force is increased by 1 N and these two new forces act at 90^@ to each other, what would be the value of the resultant ?

Two equal forces act on a body at an angle theta between them. Show that their resultant bisectos the angle theta .

If "tan" (pi/4- theta) = 1/2 find the value of sin 2 theta

If the sides of a triangle are in the ratio 5:8:11 and theta denotes the angle opposite to the largest side of the triangle, then find the value of "tan"^2 theta/2 .

The sum of magnitudes of two forces acting at a point is 16 N. The resultant has a magnitude of 8N and is perpendicular to the force of lower magnitude. The two forces are