The force on a particle of mass 10 g is `(10 hat(i) + 5 hat(j))` N. If it starts from rest what would be its position at time t = 5s ?

Explanation

We have, `F_(x)` = 10N (given)
`" "` [ `because` x component of force is 10 ]
`therefore" " a_(x) = (F_(x))/(0.01) = 1000"" m//s^(2)`
As this is a case of constant acceleration in x-direction,
`x = u_(x) t + (1)/(2) a_(x)t^(2) = 0 + (1)/(2)xx 1000 xx (5)^(2) = 12500`m
Similarly, `a_(y) = (F_(y))/(m) = (5)/(0.01) = 500 m//s^(2)`
and `y = (1)/(2)a_(y)t^(2) = (1)/(2) xx 500 xx (5)^(2) = 6250` m
Thus, the position of the particle at t = 5s is,
`vec(r) = (12500 hat(i) + 6250 hat(j) )`m.