Find out the expressions of apparent weight of a man in a lift when the lift is coming down with an acceleration (i) a = g and (iii) a `gt` g.

A person of mass m is standing in a lift. Find his apparent weight when the lift is (ii) moving downwards with uniform acceleration a( lt g),

A man of weight w is in a lift which is moving up with an acceleration a.If acceleration due to gravity is g, apparent weight of the man will be

A person of mass m is standing in a lift. Find his apparent weight when the lift is (i) moving upwards with uniform acceleration a,

A spring balance is attached to the roof of a lift. A man hanged his bag from the spring balance. The reading of the spring balance is 49N when the lift is not moving. When the lift will move downward with the acceleration 5m//s^2 , then the reading of the spring balance will be:

A man of mass 98 kg, is standing on a weighing machine in a lift. What will be the readings of the weighing machine in the following cases: (i) the lift ascends at 100 cm per second. (ii) The lift descends with an acceleration of 30 cm cdot s^(-2) ? [ g = 980 cm cdot s^(-2) ]

A lift of mass 200 kg is moving up with an acceleration of 4 m cdot s^(-2) . What is the tension in the lift cable? If the lift moves down with the same acceleration, what will be the tension in that case? [ g = 9.8 m cdot s^(-2) ]