Masses 1 kg and 3 kg move towards each other, due to their mutual attraction , no other external force acts on them. When their velocity of approach is 2 m`cdot s^(-1)` , the velocity of the centre of mass is 0.5 m`cdot s^(-1)`. What will be the velocity of the centre of mass of this system when the velocity of approach is 3 m`cdot s^(-1)`.

Explanation

The two masses may be considered to be constituents of a single system, and there is no external force acting on the system. As per the first law of motion. The velocity of the system remains constant. Velocity of a system is the velocity of its centre of mass. So the velocity of the centre of mass will continue to be 0.5 m`cdot s^(-1)`.