Home
Class 11
PHYSICS
A particle of mass 10^(-2)kg, under the ...

A particle of mass `10^(-2)`kg, under the action of a force `F(x) = - (k)/(2x^(2))` , is in motion along the positive x-direction. At time t = 0, the position of the particle is x = 1.0 m, and velcoity = 0, If k = `10^(-2)` N`cdot m^(2)`, find the velocity when the particle is at x = 0.50 m.

Text Solution

Verified by Experts

The correct Answer is:
`-1 m cdot s^(-1)`; (ii) 1.479 s
Promotional Banner

Topper's Solved these Questions

  • NEWTON'S LAWS OF MOTION

    CHHAYA PUBLICATION|Exercise ENTRANCE CORNER|5 Videos

  • NEWTON'S LAWS OF MOTION

    CHHAYA PUBLICATION|Exercise MULTIPLE CORRECT ANSWERS TYPE|2 Videos

  • NEWTON'S LAWS OF MOTION

    CHHAYA PUBLICATION|Exercise PROBLEM SET - II|26 Videos

  • NATURE OF VIBRATION

    CHHAYA PUBLICATION|Exercise EXERCISE (CBSE SCANNER)|2 Videos

  • NEWTONIAN GRAVITATION AND PLANETARY MOTION

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|19 Videos

Similar Questions

Explore conceptually related problems

The velocity of a particle moving along the positive direction of x-axis is v= Asqrt(x) , where A is a positive constant. At time t = 0 , the displacement of the particle is taken as x = 0 . (i) Express velocity and acceleration as functions of time , and (ii) find out the average velocity of the particle in the period when it travels through a distance s ?

A particle moves in the x-y plane with constant acceleration of 4 "m.s"^(-2) in the direction making an angle of 60^(@) with the x-axis. Initially, the particle is at the origin and its velocity is 5 "m.s"^(-1) along the x-axis. Find the velocity and the position of the particle at t = 5s.

Potential energy of a particle is 1/2momega^(2)x^(2) , where m and omega are constants. Prove that the motion of the particle is simple harmonic.

The position-time relation of a moving particle is x = 2t -3t^(2) . What is the maximum positive velocity of the particle?

The position-time relation of a moving particle is x = 2t -3t^(2) . When does the velocity of the particle become zero? (x is in metre and t is in second)

The position time relation of a moving particle is x = 2t - 3t^2 When does the velocity of the particle become zero? (x is in metre and t is in second)