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A block of mass M is pulled along a fric...

A block of mass M is pulled along a frictionless horizontal suface by a rope of mass m by applying a horizontal force F at the other end of the rope. The force exerted by the rope on the block is

A

`(mF)/(m + M)`

B

`(mF)/(M - m)`

C

`(MF)/(M - m)`

D

`(MF)/(m+M)`

Text Solution

Verified by Experts

Acceleration of the system,
a = `("total force")/("total mass") = (F)/(m + M)`
The force exerted by the rope on the block,
`Ma = (MF)/(m + M)`
The option D is correct.
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Knowledge Check

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