A mass of 1 kg is suspended by a thread. It is lifted up with an acceleration `4.9m/s^(2)`
(ii) lowered with an acceleration of 4.9 m`cdot s^(-2)`. The ratio of the tension on the thread is

Options

A. `3:1`
B. `1:2`
C. `1:3`
D. `2:1`

Explanation

In case of downward acceleration a, resultant force acting on the body = mg - T
`therefore` mg - T = ma or, T = m(g - a)
`therefore` The ratio of tensions on the thread in the two cases
= `(m(g + a))/(m(g - a)) = (g + a)/(g - a) = (9.8 + 4.9)/(9.8 - 4.9) = (14.7)/(4.9) = (3)/(1)`
The option A is correct.