A person of mass m is standing in a lift. Find his apparent weight when the lift is
(iii) Falling freely (g is the acceleration due to gravity).

A person of mass m is standing in a lift. Find his apparent weight when the lift is (i) moving upwards with uniform acceleration a,

A person of mass m is standing in a lift. Find his apparent weight when the lift is (ii) moving downwards with uniform acceleration a( lt g),

A lift is moving up with a constant acceleration a. A man standing on the lift, throws a ball vertically upwards with a velocity v, which returns to the thrower after a time t. show that v=(a+g) t/2 where g is the acceleration due to gravity.

Imagine earth to be a solid sphere of mass M and radius R. If the value of acceleration due to gravity at a depth d below earth's surface is same as its value at a height h above its surface and equal to (g)/(4) (where g is the value of acceleration due to gravity on the surface of earth), the ratio of (h)/(d) will be

A body of mass m is raised to a height h from a point on the surface of the earth of the earth where the acceleration due to gravity is g. Prove that the loss of weight due to variation of g is (2mgh)/R , where R is the radius of the earth.

A body of mass m is raised from the surface of the earth up to a height equal to the radius R of the earth. If the acceleration due to gravity on the earth's surface is g , prove that the potential energy of the body has increased by 1/2 mgR.

A drop of oil rises within water with an upward acceleration of alphag . If alpha is a constant and g is the acceleration due to gravity, find the specific gravity of the oil. Neglect the friction of water.