A motor car running at the rate of `7 "m.s"^(-1)` can be stopped by its brakes in 10 m. Prove that total resistance to the motion when brakes are on is one fourth of the weight of the car.

A car moving with a speed of 50 "km.h"^(-1) can be stopped by brakes after at least 6 m. What will be the minimum stopping distance, if the same car is moving at a speed of 100 "km.h"^(-1) ?

A car moving with a speed of 50 km/hr can stopped by brakes, over a distance of 6 m. If the same car is moving at a speed of 100 km/hr. the stopping distance is

A car starting with velocity 10 "m.s"^(-1) attains an acceleration 1 "m.s"^(-2) . What would be the distance traveled in time interval 10 sec?

A car is travelling towards east at 10m*s^(-1) . It takes 10s to change its direction of motion to north and continues with the same magnitude of velocity. Find the magnitude and direction of the average acceleration of the car.

A car starting with velocity 10 "m.s"^(-1) attains an acceleration 1 "m.s"^(-2) . What would be the velocity after traveling the first 100 m of the path?