What should be the maximum speed of a motor car of mass 2000 kg when it takes a circular turn of redius 100 m on a plane road? Coefficient of friction between the tyre and the road = 0.25 . Given,
g = 10 m`cdot s^(-2)`.

Explanation

Let the maximum speed of the motor car = v ,
mass of the car = m , radius of the circular path = r ,
coefficient of friction between the tyre and the road = `mu`.
In the case of maximum speed of the car,
centripetal force = limiting frictional force
or, `(mv^(2))/(r) = mu` mg
or, `" " v = sqrt(mu r g ) = sqrt( 0.25 xx 100 xx 10 ) = 15.81 m cdot s^(-1)`