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A string passes through a hole at the ce...

A string passes through a hole at the centre of a horizontal table. The upper end of the string is tied to a mass m kept on the table, and at the lower end, a body of mass M is kept hanging. If the table rotates at an angular velocity `omega`, the mass M remains at rest. Show that, `omega = sqrt((M)/(m)cdot(g)/(r))`.
[ r is the radius of the circular path along which the mass m is rotating ]

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