A stone tied to the end of a string 80 cm long is whirled in a horizontal circle with a constant speed. If the stone makes 14 revolutions in 25 s, what is the magnitude and direction of acceleration of the stone?

Explanation

According to the question,
r = 80 cm = 0.8 m
and `" "omega = 2 xx pi xx (14)/(25)` rad/s
Now, magnitude of acceleration produced,
`r omega^(2) = 0.8 xx (2 xx pi xx (14)/(25))^(2) = 9.9 m//s^(2)`
Direction of this acceleration will be along the radius of the circle towards its centre.