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A stone tied to the end of a string 80 c...

A stone tied to the end of a string 80 cm long is whirled in a horizontal circle with a constant speed. If the stone makes 14 revolutions in 25 s, what is the magnitude and direction of acceleration of the stone?

Text Solution

Verified by Experts

According to the question,
r = 80 cm = 0.8 m
and `" "omega = 2 xx pi xx (14)/(25)` rad/s
Now, magnitude of acceleration produced,
`r omega^(2) = 0.8 xx (2 xx pi xx (14)/(25))^(2) = 9.9 m//s^(2)`
Direction of this acceleration will be along the radius of the circle towards its centre.
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