A body of mass m , starting from rest , moves with constant acceleration . After a time T it attains a velocity V. Show that the work done by the body in time `t=1/2 m (V^2)/(T^2)*t^2*`

Explanation

Let the velocity attained by the body after a time t be v .
As the acceleration a is constant ,
`V=aT and v=at =(Vt)/(T)`
`therefore` Work done by the body `=1/2 mv^2= 1/2 m (V^2t^2)/(T^2)`
[ `because` initial kinetic energy =0]