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A box of mass 12 kg pushed up by a dista...

A box of mass 12 kg pushed up by a distance of 10 m on application of a 100N force along a plane of inclination `30^@`. If the coefficient of friction is `1/sqrt(3)`, find the work done against friction. `[g= 10 m*s^(s-2)]`

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Frictional force ,
`f=mu R =mu mg cos 30^@`
[Fig.1.26].

Hence work done against friction,
W=fs
`=mu mg cos 30^@ *s`
`=1/sqrt(3) xx12 xx10xxsqrt(3)/2xx10 =600J`.
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