A conservative force acting on a particle is `F=-Ax +Bx^2` where A and B are constants and x is in m. Find the potential energy associated with the force ?

Explanation

`F=-Ax +Bx^2`
`therefore` Potential energy,
`U=-intFdx=-int(-Ax+Bx^2)dx`
`=-[-(Ax^2)/(2)+(Bx^3)/(3)]+C` [where C is a constant]
`=(Ax^2)/2-(Bx^3)/3+C`