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A man of mass 100 kg climbs up a ladder ...

A man of mass 100 kg climbs up a ladder of height 10 m. The ladder makes an angle `60^@` with the horizontal . Express the work done by the man against gravity, in SI unit .`g=980 cm*s^(-2)`

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A man of mass 100 kg climbs up a ladder of length 10m. The ladder makes angle 60^@ with the horizontal . Find the work done by the man against gravity in climbing up the ladder . [g= 9.8m*s^(-2)] .

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A body of mass 10 kg is raised to a height of 10 m with an upward force of 196 N . Find the work done by the upward force and the work done against gravitation. Show that the total energy in this case is equal ot the work done by the upward force . [g=9.8 m*s^(-2) ]

Applying a force of F =196 N upwards, a body of mass 10 kg is raised up to a height of 10 m. Find the work done by the force F and the work done against gravity. Note that the work done by the force F is more than the gravitational potential energy . Show how the law of conservation of energy is still obeyed.

A body is projected with a velocity 20 m*s^(-1) , making an angle of 45^@ with the horizontal. Calculate (i) the time taken to reach the ground [g=10 m*s^(-2)] ,

A man of mass 60 kg , climbed 20 steps in 10 s carrying load of 20 kg over his head. Each step was 20 cm high . Find the power of the man.

A box of mass 12 kg pushed up by a distance of 10 m on application of a 100N force along a plane of inclination 30^@ . If the coefficient of friction is 1/sqrt(3) , find the work done against friction. [g= 10 m*s^(s-2)]

A particle of mass 100 g is suspended from the end of a weightless string of length 100 cm and is rotated in a vertical plane. The speed of the particle is 200 cm*s^(-1) when the string makes an angle of theta =60^@ with the verctcal. Determine (ii) the speed of the particle at the lowest position . Acceleration due to gravity = 980 cm *s^(-2) .

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