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A moving block having mass m , collides ...

A moving block having mass m , collides with another stationary block having mass 4m. The lighter block comes to rest after collision . When the initial velocity of the ligheter block is v, then the value of coefficient of restitution e will be

A

0.8

B

0.25

C

0.5

D

0.4

Text Solution

Verified by Experts

The correct Answer is:
B
Acceleration to law of conservation of linear momentum,
`m_1u_1+m_2u_2=m_1v_1+m_2v_2`
or, `mv+0 =0 +4 mv_2`
or, `v_2=v/4`
`therefore` Coefficient of restitution,e
`=(" relative velocity of separation after collision")/("relative velocity of approach before collision")`
`=(v/4)/v =0.25`.
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