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Two particles m(1) = 2 kg and m(2) = 3 k...

Two particles `m_(1)` = 2 kg and `m_(2)` = 3 kg have position vectors `vecr_(1)=thati+2t^(2)hatj+2thatk,"where"" "vecr_(2)=hati+2t^(3)hatj+5hatk` position vectors are in metres and time in seconds. Find (i) position vector of centre of mass (ii) velocity of centre of mass and (iii) acceleration of centre of mass.

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(i) `(1)/(5)(2t+3)i+(4t^(2)+6t^(3))j+(4t+15)k,`
(ii) `(1)/(5)[2i+(8t+18t^(2))j+4k], (iii) ((8+36t))/(5)j`
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