Home
Class 11
PHYSICS
A rod of weight W is supported by two pa...

A rod of weight W is supported by two parallel knife edge A and B and is in equilibrium in a horizontal position. The knives are at a distance d from each other. The centre of mass of the rod is at distance x from A. The normal reaction on A is

A

`(Wx)/(d)`

B

`(Wd)/(x)`

C

`(W(d-x))/(x)`

D

`(W(d-x))/(d)`

Text Solution

Verified by Experts

The correct Answer is:
D
Let the normal reactions on A and B be `N_(A)` and `N_(B)`. At equilibrium `N_(A)+N_(B)`= W
Again when the resultant torques with respect to the centre of mass is zero then
`N_(A)x+W.0-N_(B)(d-x)=0 or, N_(A)(x)/(d-x)-N_(B) = 0`
So, `N_(A)+N_(A)(x)/(d-x)=Wor,N_(A)(1+(x)/(d-x)) = W`
or, `N_(A)(d)/(d-x) = W:.N_(A) = (W(d-x))/(d)`
Promotional Banner

Topper's Solved these Questions

  • STATICS

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|3 Videos

  • STATICS

    CHHAYA PUBLICATION|Exercise EXAMINATION ARCHIVE with solutions (JEE Main )|1 Videos

  • SIMPLE HARMONIC MOTION

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|16 Videos

  • SUPERPOSITION OF WAVES

    CHHAYA PUBLICATION|Exercise CBSE Scanner|14 Videos

Similar Questions

Explore conceptually related problems

Two point charges each of magnitude +q are placed at a distance r from each other. Draw the lines of force in this case.

A large number of particles are placed around the origin each at a distance R from the origin. The distance of the centre of mass of the system from the origin is

A uniform rod of length 1 m is bent at right angles at its mid-point. What is the distance of the centre of mass from the mid-point of the rod?

Two bodies of masses m_(1) and m_(2) are separated by a distance R. The distance of the centre of mass of the bodies from the mass m_(1) is

Two particles each of mass 1 g are placed at distance of 1 m and 3 m respectively from the origin along x-axis. The centre of mass of the system from the origin is

Two point objects of mass 1.5 gm and 2.5 gm respectively are at a distance 16 cm apart, the centre of gravity is at a distance 'x' from the object of mass 1.5 gm where 'x' is

If y=4x+3 is parallel to a tangent to the parabola y^(2)=12x , then its distance from the normal parallel to the given ine is-

If y=4x+3 is parallel to a tangent to the parabola y^(2)=12 x, then its distance from the normal parallel to the given line is